**The answer is... on branch A there are 5 birds and on branch B there are 7 birds...**

Method 1: Trail and error method... like trying it starting from 1,2, and so on...

**Method 2:** Mathematical way

Let, The no. of birds on branch A =

**A**
The no. of birds on branch B =

**B**
**Step1**
A+1 = B-1 (because if we add one bird on branch A and decrease one bird on branch B, then they are equal)

So, A+1 = B-1

1+1 = B-A

or,

**2+A = B** ................ equation 1

**Step2**
2(A-1) = B+1 (because if we subtract one bird on branch A and decrease one bird on branch B, then branch B birds are double of branch A)

So, 2(A-1) = B+1

2A-2 = B+1

2A-B = 1+2

2A-B = 3

or,

**2A-3 = B** ...................equation 2

now comparing the 2 equations(by mathematical method), we get

2A-3 = 2+A

2A-A = 3+2

**A = 5** ..........so there are 5 birds in branch A

now satisfying the value in equation 1, we get

2+5 = B

or,

**B = 7**..........so there are 7 birds on branch B

... This effort was especially for Zara...

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